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[matlab] 快速求离散点刀具坐标程序

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发表于 2015-11-26 21:28:44 | 显示全部楼层 |阅读模式
本帖最后由 shouce 于 2015-11-26 21:34 编辑
2 D1 I7 H! M- _& a- F; r3 T
8 D2 c+ ?% H* C% examlpe7.m9 P0 \5 r, E! ]; V$ g0 a: d( K& C
a=0; b=2;' J/ @+ t' S$ j" P6 |. n/ z
eps1=1e-12;eps2=1e-12;8 i$ \7 g9 x# |2 K4 {" b7 |3 `
N=300;1 o  y0 x/ |; D5 b9 \. i. {  ?
A=[-0.104020146        35.0002164        -0.004160847];: _4 m; j6 R' B' {% L0 ~" O
[m,n]=size(A);
5 N8 P5 S6 e9 ?: Gfor i=1:m
5 r1 z0 H) D, q, z/ Ra1=A(i,1);b1=A(i,2);m1=A(i,3);
, H% Z. k1 V) q) c) k8 i% h% Lend
( {2 m, |; Z8 T, @8 s! d: T) ~f=@ (x) ((285+60*tan(45*pi/180)-b1*sin(x)-a1*cos(x))*(a1+b1*m1)+(60)^2*x*(sin(x)-m1*cos(x))-60*285*tan(45*pi/180)*(m1*sin(x)+cos(x)));
, Q1 l1 R# R9 S$ {$ A. OHfun=@Bisection;% g( ^7 }1 {. y9 N% s0 Z0 j
[k,x,f_value]= feval(Hfun, f,a,b,eps1,eps2,N);
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9 z6 R9 f8 z) X. @5 F" U

- j/ u' B- u  f" T0 n2 X/ x% A 为离散点坐标及导数  中心距  285  左旋  螺旋角45度     在二分法中增加一部些程序,方便了很多
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& x" t6 v+ ?, Z0 K6 i( F6 c7 U部分运行结果:
0 z4 ]% `, k7 `) ?6 p7 R" D 35, 1.303240794, 1.303240794, 1.303240794,0.000000896,
% ^0 s3 \0 h* F 36, 1.303240794, 1.303240794, 1.303240794,0.000000279,
' v) U: u' \: E4 B1 B' J 37, 1.303240794, 1.303240794, 1.303240794,-0.000000030,
9 B, w+ y! J* y8 E6 ^( A! R0 \# W 38, 1.303240794, 1.303240794, 1.303240794,0.000000124,
+ a; i  R% z3 |' v 39, 1.303240794, 1.303240794, 1.303240794,0.000000047,- R6 I, ]. n7 @7 M  X
40, 1.303240794, 1.303240794, 1.303240794,0.000000009,$ \2 j6 r0 D, b# [1 e" O4 d
41, 1.303240794, 1.303240794, 1.303240794,-0.000000011,6 k9 m5 i* A4 W: I+ E8 i2 {  A
4 P+ ?% Q3 U! R' m4 D# L  L

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