哪里有计算圆柱度误差的程序？

deltabobchen · 发表于 2006-8-17 13:53:09

对呀, 三座标可以给你自动评定的呀, 你只要结果就可以了!

luxiang821 · 发表于 2006-9-18 12:59:11

我原来也关注过一些关于形位公差评定的数学方法，不过没学过编程很想了解实现这些方法的编程算法的一些问题。不知道有没有人有兴趣谈论下，让我也长长学问。

zhuai1003 · 发表于 2006-11-2 09:05:08

我也不会编程，这儿有篇测量方面的文章，与大家共享

胡雷 · 发表于 2008-10-22 08:37:36

只是想知道这方面的计算是怎样编程的，一定要知道评价的条件，在把条件列入编程

如有不对地方多多指教

hezhikai · 发表于 2009-5-23 13:04:06

我也在找啊

foreverhua · 发表于 2010-5-27 11:04:59

我会编一点但是那个程序老是运行部出来程序如下请高手指点
function z=myfun2(x)
l=[38.8263,35.4687,25.9806,11.9948,-4.0615,-19.4158,-31.4083,-37.9757,-37.9629,-31.4080,-19.4108,-4.0573,
11.9961,25.9829,35.4653,38.8230,35.4619,25.9784,11.9957,-4.0606,-19.4149,-31.4044,-37.9785,-37.9743,-31.4093,
-19.4135,-4.0569,11.9971,25.9795,35.4636]
m=[0.0014,15.7895,28.8524,36.9273,38.6135,33.6208,22.8189,8.0678,-8.0705,-22.8217,-33.6211,-38.6107,-36.9260,
-28.8503,-15.7902,-0.0005,15.7852,28.8491,36.9245,38.6123,33.6212,22.8174,8.0687,-8.0721,-22.8214,-33.6248,
-38.6129,-36.9251,-28.8459,-15.7876]
n=[-2.0010,-2.9670,-3.9326,-4.8979,-5.8630,-6.8282,-7.7937,-8.7601,-9.7259,-10.6904,-11.6543,-12.6209,-13.5862,
-14.5507,-15.5175,-16.4838,-17.4502,-18.4149,-19.3811,-20.3463,-21.3115,-22.2779,-23.2418,-24.2071,-25.1726,
-26.1366,-27.1026,-28.0690,-29.0360,-30.0008]
z=0;
for k=1:30
r(k)=(sqrt((l(k)-x(3)*n(k)-x(1))^2+(m(k)-x(4)*n(k)-x(2))^2-x(5))^2
z=z+r(k)
end

x0=[0,0,1,1,38.000];
[x,favl,exitflag,output]=fminunc(@myfun2,x0)

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哪里有计算圆柱度误差的程序？

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