换热器的计算---请教

baboon9105

最近单位上新的项目，要选择换热器，但是如何计算？板式和管式有啥区别？

olive3000

管式的不好，建议选用板式的。

hemei

管式的冷却面积没有板式冷却面积大

天涯125

可以查阅化工版的机械设计手册第4册上面有详细的介绍换热面积的算法

13572593532

板式的换热效率高,不过最好选择好一些的制造厂家.小的可以用管式的划算.

液压青年

这得看你需要得散热功率是多大，一般大的用板式散热器

开达

COOLER
3 h6 E( y3 L$ o$ j$ m/ D. W( j3 tSELECTION
' n2 d3 o1 s/ iDesignation:
PV = Power loss [kW]
P01 = Specific cooling capacity [kW/°C]
V = Tank contents [l]
2 T& j6 I1 Y( G* T' Tρoil = Density of the oil [kg/l]
for mineral oil: 0.915 kg/l
Coil = Specific heat capacity [kJ/kgK]
9 C' g6 y' |$ e  ~2 ^1 O- X9 B$ Z4 ]for mineral oil 1.88 kJ/kgK
∆T = Temperature increase in the
system [°C]
: T; ~2 Z- ~. P) L7 U+ {t = Operating time [min]
( Q  d1 H( P* \9 N+ D2 J7 sT1 = Desired oil temperature [°C]
7 _( b" @% R! v" ~' C8 ^T3 = Ambient temperature [°C]
% r) e: `! N3 {* mExample 1:
" m9 Z; {4 {$ P3 O7 f. a/ aMeasurement of the power loss
! P: T# L, q! Yon existing units and machinery.
# m0 K5 u9 N8 j2 S/ H4 X! CFor this method the temperature
increase of the oil is measured
over a certain period. The power
4 _2 V  q9 x! uloss can be calculated from the
temperature increase.
Parameters:
The oil temperature increases
from 20 °C to 45 °C over
2 ~7 }, s& I/ m0 z. b% a# c15 minutes.
( U- o8 ?; T# o" H3 wThe tank contains 100 l.
Heat to be dissipated:
PV =（∆T × C oil × ρoil × V）/t × 60    [kW]
) u& R% t8 K. U! F, p. g* l& ?
PV =25 × 1.88 × 0.915 × 100 / (15 × 60 )
= 4.78 [kW]
8 D; a* s+ k0 `Cooler selection:
4 ^# X2 W4 N! t. G6 y5 m7 U* E– Desired oil temperature: 60 °C
& H8 n, q9 ?# \– Ambient temperature air: 30 °C

& _( c( d& l8 T5 Z0 L. e8 ?+ [, vP01 =PV    /  (T1 - T3  ) [kW/°C] =0.159
' h/ {6 ?7 S( z8 Q9 J. U1 ~& sA 10% safety margin is
recommended to allow for
element contamination, and
therefore the specific power is:
P01 × 1.1 = 0.175 kW/°C.
The power loss 0.175 kW/°C must
be dissipated by an oil cooler.
Suggestion:
) t& m5 m& `. \* ^& k! q–Cooler OK-ELH2 - 3000 rpm,
0 C8 I8 e: B1 j! P* h  h% E: ]2 AP01 = 0.20 kW/°C at 80 l/min


* F4 Z& G- @4 f7 U* Z我发了一段在上面！