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发表于 2011-8-9 23:30:24
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本帖最后由 jiangssli 于 2011-8-9 23:32 编辑
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T101M03 S500: E; t1 G( [7 N1 u
#1=200
9 k7 m$ e+ [5 F5 M2 o#2=108# S4 v9 E& Q2 E0 h0 F
#3=4.5+ V) E# R* Y; i( A% I( W
#4=2, _+ f+ T* J% Q- H* ^
#5=#2/2( p! z; ^+ \/ c7 X1 }; \
#6=#3*23 w/ K _$ l; {) Q9 u- ~
#7=#5+#4) Y$ W/ R0 k ?* o! A
#9=0.1
3 j( t) k+ e% \9 m#10=#3+#4/ s( U4 Q0 U: u; _/ c
#18=57
0 I3 h1 H4 g2 l. Z& U( e#20=44.9# L# T. O) Q/ \. O2 P
#21=ATAN[#5]/[#1]
3 i3 `8 H5 T! w; }& x8 |2 \' n% n#22=#1*2+#20
; n0 e! Q9 {7 ]- [* g#23=#22-2*[COS[#21]*#1]
6 ]/ W- G8 O: p; M1 |% f1 ]#101=[#1-[SQRT[#1*#1-#5*#5]]]*2% E4 R9 W# Z2 x
#102=[#1-[SQRT[#1*#1-[#5-#6]*[#5-#6]]]]*2
& X0 k! A# W7 D# i4 }: N5 F; |#103=[#1-[SQRT[#1*#1-[#5-#6*2]*[#5-#6*2]]]]*2
) S( ]6 H4 G" R% ~+ L2 r, z#104=[#1-[SQRT[#1*#1-[#5-#6*3]*[#5-#6*3]]]]*20 k/ i0 B( P7 X5 X6 L0 r
#105=[#1-[SQRT[#1*#1-[#5-#6*4]*[#5-#6*4]]]]*2
! U" I3 `. Y) i) f- J#106=[#1-[SQRT[#1*#1-[#5-#6*5]*[#5-#6*5]]]]*2* `1 w; S) l# J' W6 ]
#107=[#1-[SQRT[#1*#1-[#5-#6*6]*[#5-#6*6]]]]*2
7 k/ Q* G" f; R! u" A: P4 `先发一半,后面的大家想想! |
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