高度复杂的宏程序示例

孤城领主领主 · 发表于 2013-10-14 18:52:15

前一段时间在主题为五点碰数的主题里看到大家在讨论高难度的宏程序，回来之后我就把我手头上珍藏的一些极度复杂的宏程序里找出一个不那么困难的来给大家分享一下。
O9823;(REN 3- POINT BORE BOSS);
G65 P9724;
#31=#5041  (X START);
#32=#5042  (Y START);
IF  [#1NE#0]  GOTO1;
#3000=91(A INPUT MISSING);
N1;
IF[#2NE#0] GOTO2;
#3000=91(B INPUT MISSING);
N2;
IF[#3NE#0] GOTO3;
#3000=91(C INPUT MISSING);
N3;
IF[#7NE#0] GOTO4;
#3000=91(D INPUT MISSING);
N4;
#4=135;
WHILE [#4LT149]DO1;
#[#4]=#0;
#4=#4+1；
END 1;
#30=-1;
IF [#26EQ#0]GOTO5;
IF[#18NE#0]GOTO45;
#18=5*129;
N45;
IF[#18LT0]GOTO5;
#30=1;
N5;
#10=0;
N55;
G65 P9727A[#[1+#10]] Q#17 D#7 R#18 Z#26 S#500;
IF[#149NE0]GOTO21;
#[27+#10]=#124+#502-#31(SKIP+XOFF);
#[4+#10]=#125+#503-#32(SKIP+YOFF);
#10=#10+1;
IF[#10LT3]GOTO55;
#12=-[[#27*#27]+[#4*#4]];
#24=-[[#28*#28]+[#5*#5]];
#25=-[[#29*#29]+[#6*#6]];
#135=#12*[#5-#6]+#24*[#6-#4]-#25*[#5-#4];
#135=#135/[#27*[#5-#6]-#28*[#4-#6]+#29*[#4-#5]];
#135=-0.5*#125;
#136=#12*[#29-#28]+#24*[#27-#29]-#25*[#27-#28];
#136=#136/[#27*[#5-#6]-#28*[#4-#6]+#29*[#4-#5]];
#136=-0.5*#136;
#10=0;
WHILE[#10LT3]DO1;
#24=#[27+#10]-#135;
#25=#[4+#10]-#136;
G65P9731Y[-#25*#30]X[-#24*#30](ATAN);
G65P9731A[#118](ATAN);
#24=#509*COS[#118];
#[27+#10]=#[27+#10]+#24;
#25=#509*SIN[#118];
#[4+#10]=#[4+#10]+#25;
#10=#10+1;
END1;
#12=-[[#27*#27]+[#4*#4]];
#24=-[[#28*#28]+[#5*#5]];
#25=-[[#29*#29]+[#6*#6]];
#135=#12*[#5-#6]+#24*[#6-#4]-#25*[#5-#4];
#135=#135/[#27*[#5-#6]-#28*[#4-#6]+#29*[#4-#5]];
#135=-0.5*#125;
#136=#12*[#29-#28]+#24*[#27-#29]-#25*[#27-#28];
#136=#136/[#27*[#5-#6]-#28*[#4-#6]+#29*[#4-#5]];
#136=-0.5*#136;
#15=[#27-#135]*[#27-#135];
#16=[#4-#136]*[#4-#136];
#138=SQRT[#15+#16];
#135=#135+#31(XPOS);
#136=#136+#32(YPOS);
#138=#138*2(RAD*2);
#140=#135-#31(X ERROR);
#141=#136-#32(X  ERROR);
IF[#8EQ#0]GOTO8;
#138=#138+#[2000+#8](ACT SIZE COR);
N8;
#143=#138-#7(SIZE ERROR);
#145=SQRT[[#140*#140]+[#141*#141]](TP ERROR);
#146=#143*#30/2(METAL CON);
N9;
IF[#23EQ#0]GOTO10(PRINT);
G65 P9730 D#7 H#11 M#13 S#19 T#20 W#23 X#31 Y#32 E2.0;
N10;
IF[#21EQ#0]GOTO11(U UPPER TOL);
IF[ABS[#143]GE#21]GOTO23;
IF[#145GE#21]GOTO23;
N11;
IF[#11EQ#0]GOTO13;
IF[ABS[#143]LT#11]GOTO12;
#148=1;
N12;
IF[#120AND4EQ4]GOTO13;
IF[ABS[#143]LT#11]GOTO13;
G1 X#31 Y#32 F#119;
#[3006-[[#120AND8]/8*6]]=1(OUT OF TOL);
N13;
IF[#13EQ#0]GOTO15;
IF[ABS[#145]LT[#13/2]]GOTO14;
#148=2;
N14;
IF[#120AND4EQ4]GOTO15;
IF[ABS[#145]LT[#13/2]]GOTO15;
G1 X#31 Y#32 F#119;
#[3006-[[#120AND8]/8*6]]=1(OUT OF POSITION);
N15;
IF[#20EQ#0]GOTO19;
IF[ABS[#146]LT#22]GOTO19(NULL BAND);
IF[#9NE#0]GOTO16;
#9=1;
N16;
G65 P9732 T#20 C[#146*9];
IF[#26NE#0]GOTO19;
IF[#118LT[#7/2]]GOTO18;
#148=5;
N18;
IF[#120AND4EQ4]GOTO19;
IF[#118LT[#7/2]]GOTO19;
G1 X#31 Y#32 F#119;
#[3006-[[#120AND8]/8*6]]=1(DIA OFFSET TOOLARGE);
N19;
IF[#19EQ#0]GOTO24;
G65 P9732 S#19 W1.0;
GOTO24;
N21;
IF[#149NE2]GOTO22;
G1 X#31 Y#32 F#119;
#3000=93(PROBE FAIL);
N22;
G1 X#31 Y#32 F#119;
#3000=92(PROBE OPEN);
N23;
#148=3;
IF[#120AND4EQ4]GOTO24;
G1 X#31 Y#32 F#119;
#[3006-[[#120AND8]/8*6]]=1(UPPER TOL EXCEEDED);
N24;
G1 X#31 Y#32 F#119;
M99;

冷月梧桐 · 发表于 2013-10-14 19:28:23

这算难吗？？就是程序行数多些，计算多点而已。弄清理论，就好办了

刀锋365 · 发表于 2013-10-14 19:47:27

这个程序做什么用的呢

祭奠那岁月 · 发表于 2013-10-14 21:01:51

这个内容和标题好像有点不符哦

孤城领主领主 · 发表于 2013-10-14 21:12:20

冷月梧桐发表于 2013-10-14 19:28 1 e2 F# c* G, A# _7 A5 w4 O
这算难吗？？就是程序行数多些，计算多点而已。弄清理论，就好办了

那稍等，我再来一个

孤城领主领主 · 发表于 2013-10-14 21:13:00

祭奠那岁月发表于 2013-10-14 21:01
; ]7 w7 K# i" P8 e8 [1 E这个内容和标题好像有点不符哦

稍等，马上就上好菜

孤城领主领主 · 发表于 2013-10-14 21:20:27

O9730(REN PRINT);
(40120520 . OEB);
POPEN;
IF[#121NE#0]GOTO1;
#121=1;
N1;
IF[#122NE#0]GOTO2;
#122=1;
N2;
IF[#23NE2]GOTO3;
#121=#121+1;
#122=1;
N3;
DPRNT[    ];
DPRNT[----------------];
DPRNT[***COMPONENT*NO*#121[60]****FEATURE*NO*#122[40]];
DPRNT[----------------];
#122=#122+1;
IF[#20EQ#0]GOTO4;
DPRNT[TOOL *OFFSET*H#20[40]];
N4;
IF[#19EQ#0]GOTO20;
DPRNT[WORK *OFFSET*S#19[30]];
N20;
IF[#18EQ#0]GOTO30;
(PCD INPUT);
#28=#135-#24+#4;
#29=#136-#25+#5;
DPRNT[PCD*FEATURE*NO*#147[30]];
DPRNT[INC*X#4[44]****ACTUAL*#128[44]];
DPRNT[INC*Y#5[44]***ACTUAL*#29[44]];
DPRNT[PCD*#18[44]***ACTUAL*#137[44]***DEV*#142[34]];
DPRNT[ANG*#1[44]***ACTUAL*#139[44]***DEV*#144[34]];
DPRNT[  ];
#1=#0;
N30(D INPUT);
IF[#7EQ#0]GOTO40;
IF[#8EQ2]GOTO31;
IF[#11NE#0]GOTO31;
IF[#20NE#0]GOTO31;
GOTO35;
N31(SIZE DATA);
#14=1;
IF[#11NE#0]GOTO32;
DPRNT[SIZE*D#7[44]***ACTUAL*#138[44]***DEV*#143[34]];
GOTO40;
N32;
DPRNT[SIZE*D#7[44]***ACTUAL*#138[44]***TOL*#11[24]**DEV*#143[34]];
IF[ABS[#143]LE#11]GOTO40;
#32=40;
GOTO110;
N35(POS);
IF[#13NE#0]GOTO36;
DPRNT[POSN*R#7[44]***ACTUAL*#138[44]***DEV*#143[34]];
GOTO40;
N36;
DPRNT[POSN*R#7[44]***ACTUAL*#138[44]***TOL*TP*#13[24]**DEV*#143[34]];
N40(X INPUT);
IF[#24EQ#0]GOTO50;
IF[#14EQ1]GOTO45;
IF[#11NE#0]GOTO41;
IF[#20NE#0]GOTO41;
GOTO45;
N41(SIZE DATA);
#14=1;
IF[#11NE#0]GOTO42;
DPRNT[SIZE*X#24[44]***ACTUAL*#138[44]***DEV*#143[34]];
GOTO50;
N42;
DPRNT[SIZE*X#24[44]***ACTUAL*#138[44]***TOL*#11[24]**DEV*#143[34]];
IF[ABS[#143]LE[#11]]GOTO50;
#32=50;
GOTO110;
N45(POS);
IF[#13NE#0]GOTO46;
DPRNT[POSN*X#24[44]***ACTUAL*#135[44]***DEV*#140[34]];
GOTO50;
N46;
DPRNT[POSN*X#24[44]***ACTUAL*#135[44]***TOL*TP*#13[24]**DEV*#140[34]];
N50(Y INPUT);
IF[#25EQ#0]GOTO60;
IF[#14EQ1]GOTO55;
IF[#11NE#0]GOTO51;
IF[#20NE#0]GOTO51;
GOTO55;
N51(SIZE DATA);
#14=1;
IF[#11NE#0]GOTO52;
DPRNT[SIZE*Y#25[44]***ACTUAL*#138[44]***DEV*#143[34]];
GOTO60;
N52;
DPRNT[SIZE*Y#25[44]***ACTUAL*#138[44]***TOL*#11[24]**DEV*#143[34]];
IF[ABS[#143]LE#11]GOTO60;
#32=60;
GOTO110;
N55(POS);
IF[#13NE#0]GOTO56;
DPRNT[POSN*Y#25[44]***ACTUAL*#136[44]***DEV*#141[34]];
GOTO60;
N56;
DPRNT[POSN*Y#25[44]***ACTUAL*#136[44]***TOL*TP*#13[24]**DEV*#141[34]];
N60(Z INPUT);
IF[#26EQ#0]GOTO67;
IF[#14EQ1]GOTO65;
IF[#11NE#0]GOTO61;
IF[#20NE#0]GOTO61;
GOTO65;
N61(SIZE DATA);
#14=1;
IF[#11NE#0]GOTO62;
DPRNT[SIZE*Z#26[44]***ACTUAL*#138[44]***DEV*#143[34]];
GOTO70;
N62;
DPRNT[SIZE*Z#26[44]***ACTUAL*#138[44]***TOL*#11[24]**DEV*#143[34]];
IF[ABS[#143]LE#11]GOTO70;
#32=70;
GOTO110;
N65(POS);
IF[#13NE#0]GOTO66;
DPRNT[POSN*Z#26[44]***ACTUAL*#137[44]***DEV*#142[34]];
GOTO70;
N66;
DPRNT[POSN*Z#26[44]***ACTUAL*#137[44]***TOL*TP*#13[24]**DEV*#142[34]];
N67;
IF[#13EQ#0]GOTO70;
IF[ABS[#145]LE[#13/2]]GOTO70;
#32=70;
GOTO120;
N70(ANG INPUT);
IF[#1EQ#0]GOTO80;
IF[#17NE#0]GOTO71;
DPRNT[ANG*#1[44]***ACTUAL*#139[44]***TOL*#17[24]**DEV*#144[34]];
IF[ABS[#144]LE#17]GOTO80;
#28=#144;
#29=#17;
#32=80;
GOTO130;
N80;
IF[#2EQ#0]GOTO199;
(ANG2 INPUT);
IF[#3NE#0]GOTO81;
DPRNT[ANG*#2[44]***ACTUAL*#142[44]**DEV*#143[34]];
GOTO199;
N81;
DPRNT[ANG*#2[44]***ACTUAL*#142[44]***TOL*#3[24]**DEV*#143[34]];
IF[ABS[#143]LE#3]GOTO199;
#28=#143;
#29=#3;
#32=199;
GOTO130;
N110(SIZE TOL);
IF[#143LT0]GOTO111;
#31=#143-#11;
GOTO12;
N111;
#31=#143+#11;
N112;
DPRNT[ ];
DPRNT[*******++++++OUT*OF*TOL++++*ERROR*#31[34]];
DPRNT[ ];
GOTO#32;
N120(POS TOL);
IF[#15EQ1]GOTO#32;
#28=#145-#13/2;
DPRNT[ ];
DPRNT[******+++++OUT*OF*POS++++*ERROR*TP*#28[34]*RADIAL];
DPRNT[    ];
#15=1;
GOTO#32;
N130(ANG TOL);
IF[#28LT0]GOTO131;
#31=#28-#29;
GOTO132;
N131;
#31=#28+#29;
N32;
DPRNT[    ];
DPRNT[****++++++ANG*OUT*OF*TOL++++*ERROR*#31[34]];
DPRNT[    ];
GOTO#32;
N199;
PCLOS;
M99;

机械梦想者2 · 发表于 2013-10-14 22:00:23

直接来个流程图呀

门童 · 发表于 2013-10-14 22:31:51

孤城领主领主发表于 2013-10-14 21:20
9 j. f! G( t4 g) |O9730(REN PRINT);$ o9 w! E6 D2 t; C1 Z0 A4 n
(40120520 . OEB);; k& A# p0 w2 l9 W3 v
POPEN;

没发现难在哪里？是难看吗？

海底捞月 · 发表于 2013-10-14 22:45:10

看着就晕

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